Prove that 〖log〗_a〖m^n 〗=n 〖log〗_am.
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
Prove that 〖log〗_a〖m^n 〗=n 〖log〗_am.
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.