1,26601056e+26

asked by guest
on Nov 24, 2024 at 4:41 pm



MathBot Answer:

The sum of \(1\) and \(26601056 e + 26\) is:

\[\begin{aligned}&=\left(1\right) + \left(26601056 e + 26\right) \\\\ &= 27 + 26601056 e \\\\\end{aligned}\]

The difference of \(1\) and \(26601056 e + 26\) is:

\[\begin{aligned}&=\left(1\right) - \left(26601056 e + 26\right) \\\\ &= - 26601056 e - 25 \\\\\end{aligned}\]

The product of \(1\) and \(26601056 e + 26\) is:

\[\begin{aligned}&=\left(1\right) \cdot \left(26601056 e + 26\right) \\\\ &= 26 + 26601056 e \\\\ &=26 + 26601056 e \\\\\end{aligned}\]

The quotient of \(1\) and \(26601056 e + 26\) is:

\[\begin{aligned}&= \frac{\left(1\right)}{\left(26601056 e + 26\right)} \\\\ &= \frac{1}{26 + 26601056 e} \\\\ &= \frac{1}{2 \cdot \left(13 + 13300528 e\right)} \\\\\end{aligned}\]

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