y^2/3 + 3y^-1 -2 when y =1/8
You asked:
Calculate the value of \(\frac{{y}^{2}}{3} + 3 {y}^{-1} - 2\) when \(y = \frac{1}{8}\).
MathBot Answer:
\[\frac{{y}^{2}}{3} + 3 {y}^{-1} - 2 = \frac{{\left( \frac{1}{8} \right)}^{2}}{3} + 3 {\left( \frac{1}{8} \right)}^{-1} - 2 = \frac{4225}{192}\]