(P-5q)(p+3q)
asked by guest on Mar 22, 2025 at 9:29 pm
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MathBot Answer:
(P−5q)(p+3q)=(P−5q)(p+3q)\displaystyle \left(P - 5 q\right) \left(p + 3 q\right) = \left(P - 5 q\right) \left(p + 3 q\right) (P−5q)(p+3q)=(P−5q)(p+3q)
(P−5q)(p+3q)=Pp+3Pq−5pq−15q2\left(P - 5 q\right) \left(p + 3 q\right) = P p + 3 P q - 5 p q - 15 q^{2}(P−5q)(p+3q)=Pp+3Pq−5pq−15q2