x→0
lim
x
2/3
−sin(x
2/3
)
x−ln(1+x)
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
x→0
lim
x
2/3
−sin(x
2/3
)
x−ln(1+x)
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.