log^2 (x+3) = -1
You asked:
Solve the equation \({\log\left( x + 3 \right)}^{2} = -1\) for the variable \(x\).
MathBot Answer:
The 2 solutions to the equation are: \[\begin{aligned}x &= -3 + \cos{\left(1 \right)} + i \sin{\left(1 \right)} \approx -2.4596977 + 0.84147098 i\\x &= -3 + \cos{\left(1 \right)} - i \sin{\left(1 \right)} \approx -2.4596977 -0.84147098 i\end{aligned}\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).