(2√3 - 3√2) ^2

asked by guest
on Mar 26, 2025 at 9:01 pm



You asked:

Evaluate the expression: (23−32)2{\left( 2 \sqrt{3} - 3 \sqrt{2} \right)}^{2}

MathBot Answer:

(23−32)2=(−32+23)2≈0.6061230866018628216325911035293{\left( 2 \sqrt{3} - 3 \sqrt{2} \right)}^{2} = \left(- 3 \sqrt{2} + 2 \sqrt{3}\right)^{2} \approx 0.6061230866018628216325911035293

(23−32)2=(2⋅3−3⋅2)2=(−3⋅2+2⋅3)2\begin{aligned}{\left( 2 \sqrt{3} - 3 \sqrt{2} \right)}^{2}&=\left(2 \cdot \sqrt{3} - 3 \cdot \sqrt{2}\right)^{2}\\&=\left(-3 \cdot \sqrt{2} + 2 \cdot \sqrt{3}\right)^{2}\end{aligned}

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