p+$\frac{1}{p}$= $\sqrt{6}$, $p^{2}$+$\frac{1}{p^2}$ =?
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p+$\frac{1}{p}$= $\sqrt{6}$, $p^{2}$+$\frac{1}{p^2}$ =?
MathBot Answer:
MathBot is working on a solution to your problem.