(p+1)(p^2-p+1)

asked by guest
on Mar 28, 2025 at 4:07 am



You asked:

Evaluate the expression: (p+1)(p2−p+1)\left(p + 1\right) \left({p}^{2} - p + 1\right)

MathBot Answer:

Evaluated



(p+1)(p2−p+1)=(p+1)(p2−p+1)\displaystyle \left(p + 1\right) \left({p}^{2} - p + 1\right) = \left(p + 1\right) \left(p^{2} - p + 1\right)

Expanded

(p+1)(p2−p+1)=p3+1\left(p + 1\right) \left({p}^{2} - p + 1\right) = p^{3} + 1

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