(-3x^2+6x^3-4-x)/(2x+1)

asked by guest
on Oct 21, 2024 at 5:38 pm



You asked:

Evaluate the expression: \(\frac{-\left( 3 \cdot {x}^{2} \right) + 6 \cdot {x}^{3} - 4 - x}{2 x + 1}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{-\left( 3 \cdot {x}^{2} \right) + 6 \cdot {x}^{3} - 4 - x}{2 x + 1} = \frac{6 x^{3} - 3 x^{2} - x - 4}{2 x + 1} \)

Expanded

\[\frac{-\left( 3 \cdot {x}^{2} \right) + 6 \cdot {x}^{3} - 4 - x}{2 x + 1} = \frac{6 x^{3}}{2 x + 1} - \frac{3 x^{2}}{2 x + 1} - \frac{x}{2 x + 1} - \frac{4}{2 x + 1}\]

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