Math Problem Solver

\[ 1\frac{1}{3} - 2 = - \frac{2}{3} = -0.\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{1}\), \(\frac{1}{3}\), and \(\frac{-2}{1}\) is \(3\). \[ \begin{aligned} 1\frac{1}{3} - 2 &= \frac{1 \cdot 3}{1 \cdot 3} + \frac{1 \cdot 1}{3 \cdot 1} + \frac{-2 \cdot 3}{1 \cdot 3} \\ &= \frac{3 + 1 + -6}{3} \\ &= \frac{-2}{3} \end{aligned} \]