18abc−19bc+21c÷6c
asked by guest on Mar 26, 2025 at 4:32 pm
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MathBot Answer:
18abc−19bc+21c6c=18abc−19bc+7218 a b c - 19 b c + \frac{21 c}{6 c} = 18 a b c - 19 b c + \frac{7}{2}18abc−19bc+6c21c=18abc−19bc+27