z^2=((1-i)^16)/i
You asked:
Investigate the equation: \({z}^{2} = \frac{{\left( 1 - i \right)}^{16}}{i}\).
MathBot Answer:
The 2 solutions to the equation are: \[\begin{aligned}z &= - 8 \sqrt{2} + 8 \sqrt{2} i \approx -11.313708 + 11.313708 i\\z &= 8 \sqrt{2} - 8 \sqrt{2} i \approx 11.313708 -11.313708 i\end{aligned}\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).