(3x^3 + 7x^2 - 4) / (x+1)

asked by guest
on Sep 20, 2024 at 3:24 am



You asked:

Evaluate the expression: \(\frac{3 \cdot {x}^{3} + 7 \cdot {x}^{2} - 4}{x + 1}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{3 \cdot {x}^{3} + 7 \cdot {x}^{2} - 4}{x + 1} = \frac{3 x^{3} + 7 x^{2} - 4}{x + 1} \)


Expanded

\[\frac{3 \cdot {x}^{3} + 7 \cdot {x}^{2} - 4}{x + 1} = \frac{3 x^{3}}{x + 1} + \frac{7 x^{2}}{x + 1} - \frac{4}{x + 1}\]


Factored

\[\frac{3 \cdot {x}^{3} + 7 \cdot {x}^{2} - 4}{x + 1} = \left(3 x - 2\right) \left(x + 2\right)\]