(3a+4b)(3a-4b)
asked by guest on Mar 17, 2025 at 5:38 am
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MathBot Answer:
(3a+4b)(3a−4b)=(3a−4b)(3a+4b)\displaystyle \left(3 a + 4 b\right) \left(3 a - 4 b\right) = \left(3 a - 4 b\right) \left(3 a + 4 b\right) (3a+4b)(3a−4b)=(3a−4b)(3a+4b)
(3a+4b)(3a−4b)=9a2−16b2\left(3 a + 4 b\right) \left(3 a - 4 b\right) = 9 a^{2} - 16 b^{2}(3a+4b)(3a−4b)=9a2−16b2