Given 2⋅ex=5+2⋅e−y 2 \cdot {e}^{x} = 5 + 2 \cdot {e}^{-y} 2⋅ex=5+2⋅e−y, 3⋅e−x=−5+3⋅ey 3 \cdot {e}^{-x} = -5 + 3 \cdot {e}^{y} 3⋅e−x=−5+3⋅ey, evaluate x x x, y y y
asked by guest on Nov 14, 2024 at 6:09 am
