17+x^4+18x^2=0

asked by guest
on Sep 20, 2024 at 10:52 am



You asked:

Solve the equation \(17 + {x}^{4} + 18 \cdot {x}^{2} = 0\) for the variable \(x\).

MathBot Answer:

The 4 solutions to the equation are: \[\begin{aligned}x &= i\\x &= -i\\x &= \sqrt{17} i \approx 4.1231056 i\\x &= - \sqrt{17} i \approx -4.1231056 i\end{aligned}\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).