$x^{4}$-13 $x^{3}$ +62 $x^{2}$-128 $x^{1}$ +96=0
You asked:
Solve the equation \({x}^{4} - 13 {x}^{3} + 62 {x}^{2} - 128 {x}^{1} + 96 = 0\) for the variable \(x\).
MathBot Answer:
The 3 solutions to the equation are: \[\begin{aligned}x &= 2\\x &= 3\\x &= 4\end{aligned}\]