\frac{8u^4}{16v}\div \frac{7v^2}{64u}
asked by guest on Mar 25, 2025 at 4:22 pm
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MathBot Answer:
8u416v7v264u=32u57v3\frac{\frac{8 {u}^{4}}{16 v}}{\frac{7 {v}^{2}}{64 u}} = \frac{32 u^{5}}{7 v^{3}}64u7v216v8u4=7v332u5