2^n=192196

solve n

asked by guest
on Apr 07, 2025 at 3:32 am



You asked:

Solve the equation 2n=192196{2}^{n} = 192196 for the unknown nn.

MathBot Answer:

The solution is: n=2+log⁡(48049)log⁡(2)≈17.552219n = 2 + \frac{\log{\left(48049 \right)}}{\log{\left(2 \right)}} \approx 17.552219

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