0.45x^2 -10x +6545=0
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MathBot Answer:
Solve by quadratic formula:
Given a quadratic equation \(a x^{2} + b x + c = 0\), where \(a\), \(b\), \(c\) are constants and \(a \ne 0\), the solutions are given by the quadratic formula: \[x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\] In this case \(a=\frac{9}{20}\), \(b=-10\), and \(c=6545\).
The discriminant is the quantity under the square root sign in the quadratic formula, and its sign determines the number of solutions to the quadratic equation when the coefficients are real. The discriminant is:\[b^{2}-4ac = \left(-10\right)^{2} - \frac{9}{5} \cdot 6545=-11681 < 0\] The discriminant is less than zero, so this quadratic equation has two solutions with non-zero imaginary part.
The two solutions are: \[x = \frac{\left(-1\right) \left(-10\right) + \sqrt{-11681}}{2 \cdot \frac{9}{20}} = \frac{100}{9} + \frac{10 \sqrt{11681} i}{9} \approx 11.\overline{1} + 120.08742 i\] \[x = \frac{\left(-1\right) \left(-10\right) - \sqrt{-11681}}{2 \cdot \frac{9}{20}} = \frac{100}{9} - \frac{10 \sqrt{11681} i}{9} \approx 11.\overline{1} -120.08742 i\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).
\(i\) is the imaginary unit, defined as \(i^2 = -1\).