Sean Π : 2𝑥 − 𝑦 + 𝑧 = 1, 𝐿: (𝑥, 𝑦, 𝑧) = λ. (0, 1, 2) + (− 1, 3, 8)
y 𝐿': (𝑥, 𝑦, 𝑧) = λ. (− 1, 2, 5) + (0, 1, 3)
a) Hallar 𝐿'' / ( 𝐿'' ⊥ Π 𝑦 𝐿 ∩ 𝐿' ϵ 𝐿''
b) Hallar Π ∩ Π' si Π' contiene los puntos (1, 1, 0), (− 2, 6, 2) y (0,2,1)
c) Hallar 𝐿' ∩ Π y Π'' / ( 𝐿 ⊆ Π'' 𝑦 𝐿' ⊆ Π'')
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