(3-2i)x + (1+2i)y-1 =0
(3+2i)x - (1-2i) y-1 =0
You asked:
Solve the system of equations:\[\begin{aligned}\left(3 - 2 i\right) \cdot x + \left(1 + 2 i\right) \cdot y - 1 &= 0\\\left(3 + 2 i\right) \cdot x - \left(1 - 2 i\right) \cdot y - 1 &= 0\end{aligned}\]