(2x-1)(x-5)(x+6)
asked by guest on Feb 01, 2025 at 3:06 am
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MathBot Answer:
(2x−1)(x−5)(x+6)=(2x−1)(x−5)(x+6)\displaystyle \left(2 x - 1\right) \left(x - 5\right) \left(x + 6\right) = \left(2 x - 1\right) \left(x - 5\right) \left(x + 6\right) (2x−1)(x−5)(x+6)=(2x−1)(x−5)(x+6)
(2x−1)(x−5)(x+6)=2x3+x2−61x+30\left(2 x - 1\right) \left(x - 5\right) \left(x + 6\right) = 2 x^{3} + x^{2} - 61 x + 30(2x−1)(x−5)(x+6)=2x3+x2−61x+30