y=x^4+6x^3-x^2-6x find roots

asked by guest
on Oct 16, 2024 at 1:45 am



You asked:

Find the zeros of \(y = {x}^{4} + 6 \cdot {x}^{3} - {x}^{2} - 6 x\)

MathBot Answer:

The zeros of \(y = x^{4} + 6 x^{3} - x^{2} - 6 x\) are: $$\begin{align*}x &= -6\\x &= -1\\x &= 0\\x &= 1\end{align*}$$