(105/100)^(n-1)=2

asked by guest
on Jan 13, 2025 at 10:38 pm



You asked:

Solve the equation (105100)n−1=2{\left( \frac{105}{100} \right)}^{n - 1} = 2 for the variable nn.

MathBot Answer:

The solution is: n=−−log⁡(20)+log⁡(2)+log⁡(21)−log⁡(21)+log⁡(20)≈15.206699n = - \frac{- \log{\left(20 \right)} + \log{\left(2 \right)} + \log{\left(21 \right)}}{- \log{\left(21 \right)} + \log{\left(20 \right)}} \approx 15.206699

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