2^(2x+1)=17×2^x+2^3
You asked:
Solve the equation \({2}^{2 x + 1} = 17 \cdot {2}^{x} + {2}^{3}\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{\log{\left(\frac{17}{4} + \frac{\sqrt{353}}{4} \right)}}{\log{\left(2 \right)}} \approx 3.1614159\]