solve 4^2x-1=5^x+2

asked by guest
on Nov 15, 2024 at 2:55 pm



You asked:

Solve the equation 42x−1=5x+2{4}^{2} x - 1 = {5}^{x} + 2 for the variable xx.

MathBot Answer:

The 2 solutions to the equation are: x=0.15955262130551873920785492136348292719508603213+3log⁡(5)16log⁡(5)≈0.28663562x=3.13876284089968049113325414533092871532249607949+3log⁡(5)16log⁡(5)≈2.137723\begin{aligned}x &= \frac{0.15955262130551873920785492136348292719508603213 + \frac{3 \log{\left(5 \right)}}{16}}{\log{\left(5 \right)}} \approx 0.28663562\\x &= \frac{3.13876284089968049113325414533092871532249607949 + \frac{3 \log{\left(5 \right)}}{16}}{\log{\left(5 \right)}} \approx 2.137723\end{aligned}

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