9^x+3^x+1-18=0
You asked:
Solve the equation \({9}^{x} + {3}^{x} + 1 - 18 = 0\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{\log{\left(- \frac{1}{2} + \frac{\sqrt{69}}{2} \right)}}{\log{\left(3 \right)}} \approx 1.179337\]