5=25a+5b+c
8=16a+4b+C
-6=4a-2b+c
You asked:
Solve the system of equations:\[\begin{aligned}5 &= 25 a + 5 b + c\\8 &= 16 a + 4 b + C\\-6 &= 4 a - 2 b + c\end{aligned}\]
MathBot Answer:
The system of equations has infinitely many solutions.
$$\begin{aligned}C &= \frac{2 c}{5} + \frac{20}{7}\\a &= - \frac{c}{10} - \frac{2}{7}\\b &= \frac{3 c}{10} + \frac{17}{7}\end{aligned}$$
\(c\) is a free variable.