factor x^2y^2+3xy^2-2x^2-6x

asked by guest
on Apr 06, 2025 at 9:21 am



You asked:

Factor the expression: x2y2+3xy22x26x\displaystyle {x}^{2} {y}^{2} + 3 x {y}^{2} - 2 {x}^{2} - 6 x

MathBot Answer:

The polynomial factors into the product: x2y2+3xy22x26x=x(y22)(x+3){x}^{2} {y}^{2} + 3 x {y}^{2} - 2 {x}^{2} - 6 x = x \left(y^{2} - 2\right) \left(x + 3\right)