\left(2+\sqrt{3}\right)\sqrt{2-\sqrt{3}}\cdot 2=\sqrt{6}+\sqrt{2}

asked by guest
on Jan 23, 2025 at 2:38 am



You asked:

Investigate the equation: \(\left(2 + \sqrt{3}\right) \cdot \sqrt{2 - \sqrt{3}} \cdot 2 = \sqrt{6} + \sqrt{2}\).

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