A sin (30) - B cos (25) = 0

A cos (36) - B sin (60) +10 = 0

asked by guest
on Jan 26, 2025 at 2:16 pm



You asked:

Solve the system of equations:Asin⁡(30)−Bcos⁡(25)=0Acos⁡(36)−Bsin⁡(60)+10=0\begin{aligned}A \sin\left( 30 \right) - B \cos\left( 25 \right) &= 0\\A \cos\left( 36 \right) - B \sin\left( 60 \right) + 10 &= 0\end{aligned}

MathBot Answer:

The system of equations has one solution.A=−10cos⁡(25)(cos⁡(25)cos⁡(36)sin⁡(30)−sin⁡(60))sin⁡(30)A = - \frac{10 \cos{\left(25 \right)}}{\left(\frac{\cos{\left(25 \right)} \cos{\left(36 \right)}}{\sin{\left(30 \right)}} - \sin{\left(60 \right)}\right) \sin{\left(30 \right)}} B=−10cos⁡(25)cos⁡(36)sin⁡(30)−sin⁡(60)B = - \frac{10}{\frac{\cos{\left(25 \right)} \cos{\left(36 \right)}}{\sin{\left(30 \right)}} - \sin{\left(60 \right)}}
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