sum_(k=1)^(2 n) (-1)^k 2^(k - 1) binomial(2 n, k) = 0
You asked:
Investigate the equation: \(\sum_{k = 1}^{2 n} {{\left( -1 \right)}^{k} \cdot {2}^{k - 1} \cdot \operatorname{C}(2 n, k)} = 0\).
MathBot Answer:
No solution.
sum_(k=1)^(2 n) (-1)^k 2^(k - 1) binomial(2 n, k) = 0
You asked:
MathBot Answer:
No solution.