0.68*20*x*56.5^2*(2.5/1.4)*(1-0.4x)

asked by guest
on Mar 17, 2025 at 5:54 am



You asked:

Evaluate the expression: 0.68⋅20x⋅56.52⋅2.51.4(1−0.4x)0.68 \cdot 20 x \cdot {56.5}^{2} \cdot \frac{2.5}{1.4} \left(1 - 0.4 x\right)

MathBot Answer:

Evaluated



0.68⋅20x⋅56.52⋅2.51.4(1−0.4x)=1085365x(1−2x5)14\displaystyle 0.68 \cdot 20 x \cdot {56.5}^{2} \cdot \frac{2.5}{1.4} \left(1 - 0.4 x\right) = \frac{1085365 x \left(1 - \frac{2 x}{5}\right)}{14}

Expanded

0.68⋅20x⋅56.52⋅2.51.4(1−0.4x)=−217073x27+1085365x140.68 \cdot 20 x \cdot {56.5}^{2} \cdot \frac{2.5}{1.4} \left(1 - 0.4 x\right) = - \frac{217073 x^{2}}{7} + \frac{1085365 x}{14}

Factored

0.68⋅20x⋅56.52⋅2.51.4(1−0.4x)=−217073x(2x−5)140.68 \cdot 20 x \cdot {56.5}^{2} \cdot \frac{2.5}{1.4} \left(1 - 0.4 x\right) = - \frac{217073 x \left(2 x - 5\right)}{14}

+ Submit Question