solve (D^2+2D+2)y=e^-x+sin2x

asked by guest
on Apr 04, 2025 at 8:25 am



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Investigate the equation: (D2+2D+2)⋅y=e−x+sin⁡(2x)\left({D}^{2} + 2 D + 2\right) \cdot y = {e}^{-x} + \sin\left( 2 x \right).

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