(x+2)(x+2+i)(x+2-i)

asked by guest
on Oct 26, 2024 at 5:32 pm



You asked:

Evaluate the expression: \(\left(x + 2\right) \cdot \left(x + 2 + i\right) \cdot \left(x + 2 - i\right)\)

MathBot Answer:

Evaluated



\(\displaystyle \left(x + 2\right) \cdot \left(x + 2 + i\right) \cdot \left(x + 2 - i\right) = \left(x + 2\right) \left(x + 2 - i\right) \left(x + 2 + i\right) \)

Expanded

\[\left(x + 2\right) \cdot \left(x + 2 + i\right) \cdot \left(x + 2 - i\right) = x^{3} + 6 x^{2} + 13 x + 10\]

\(i\) is the imaginary unit, defined as \(i^2 = -1\).

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