(x+2)(x+2+i)(x+2-i)
You asked:
Evaluate the expression: \(\left(x + 2\right) \cdot \left(x + 2 + i\right) \cdot \left(x + 2 - i\right)\)
MathBot Answer:
Evaluated
\(\displaystyle \left(x + 2\right) \cdot \left(x + 2 + i\right) \cdot \left(x + 2 - i\right) = \left(x + 2\right) \left(x + 2 - i\right) \left(x + 2 + i\right) \)
Expanded
\[\left(x + 2\right) \cdot \left(x + 2 + i\right) \cdot \left(x + 2 - i\right) = x^{3} + 6 x^{2} + 13 x + 10\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).