(1.30 *10E+09) * (0.5*10^-9) * C = 0.6

asked by guest
on Oct 22, 2024 at 7:30 pm



You asked:

Investigate the equation: \(\left(1.30 \cdot 10 E + 09\right) \cdot 0.5 \cdot {10}^{-9} \cdot C = 0.6\).

MathBot Answer:

The graph of the equation \(\left(1.30 \cdot 10 E + 09\right) \cdot 0.5 \cdot {10}^{-9} \cdot C = 0.6\) is a hyperbola.


The coordinates of its foci are: \(\left(- \frac{20000 \sqrt{78}}{13}, - \frac{20000 \sqrt{78}}{13} - \frac{9}{13}\right)\) and \(\left(\frac{20000 \sqrt{78}}{13}, - \frac{9}{13} + \frac{20000 \sqrt{78}}{13}\right)\).

The coordinates of its vertices are: \(\left(- \frac{20000 \sqrt{39}}{13}, - \frac{20000 \sqrt{39}}{13} - \frac{9}{13}\right)\) and \(\left(\frac{20000 \sqrt{39}}{13}, - \frac{9}{13} + \frac{20000 \sqrt{39}}{13}\right)\).

The asymptotes have equations: \(- 80000 \sqrt{39} C = 0\) and \(- 1040000 \sqrt{39} E - 720000 \sqrt{39} = 0\).