5460(1.019)^n = 8190
asked by guest on Apr 05, 2025 at 12:19 am
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MathBot Answer:
The solution is: n=−log(3)+log(2)−log(1019)+3log(10)≈21.542365n = \frac{- \log{\left(3 \right)} + \log{\left(2 \right)}}{- \log{\left(1019 \right)} + 3 \log{\left(10 \right)}} \approx 21.542365n=−log(1019)+3log(10)−log(3)+log(2)≈21.542365