(-x/1-x)^3-3(-x/1-x)-1
asked by guest on Apr 06, 2025 at 8:58 pm
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MathBot Answer:
(−x1−x)3−3(−x1−x)−1=−8x3+6x−1\displaystyle {\left( \frac{-x}{1} - x \right)}^{3} - 3 \left(\frac{-x}{1} - x\right) - 1 = - 8 x^{3} + 6 x - 1 (1−x−x)3−3(1−x−x)−1=−8x3+6x−1
(−x1−x)3−3(−x1−x)−1=−8x3+6x−1{\left( \frac{-x}{1} - x \right)}^{3} - 3 \left(\frac{-x}{1} - x\right) - 1 = - 8 x^{3} + 6 x - 1(1−x−x)3−3(1−x−x)−1=−8x3+6x−1