4z − 2z(1 + 4) − 36 for z = 5
asked by guest
on Nov 20, 2024 at 7:31 pm
You asked:
Calculate the value of
4z−2z(1+4)−36 when
z=5.
MathBot Answer:
4z−2z(1+4)−36=−66
−2z(1+4)+4z−36=4⋅5−2⋅(1+4)5−36=−2⋅(1+4)5+20−36=−2⋅52+20−36=−2⋅25+20−36=−50+20−36=−66