x-y-z=1

3x-2y+2z=3

2x-y+3z=-1

asked by guest
on Mar 17, 2025 at 3:25 am



You asked:

Solve the system of equations:xyz=13x2y+2z=32xy+3z=1\begin{aligned}x - y - z &= 1\\3 x - 2 y + 2 z &= 3\\2 x - y + 3 z &= -1\end{aligned}

MathBot Answer:

The system of equations has no solution.