(2x+3)(3x+2)=6(x-1)(x-2)
You asked:
Solve the equation \(\left(2 x + 3\right) \left(3 x + 2\right) = 6 \left(x - 1\right) \left(x - 2\right)\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{6}{31} = 0.\overline{193548387096774}\]
\[\begin{aligned}6 x^{2} + 13 x + 6 &= 6 x^{2} - 18 x + 12\\31 x &= 6\\x &= \frac{6}{31}\end{aligned}\]