\frac{r}{2q}\times \frac{3r}{5q}\times 30r
asked by guest on Mar 25, 2025 at 6:19 pm
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MathBot Answer:
r2q⋅3r5q⋅30r=9r3q2\frac{r}{2 q} \cdot \frac{3 r}{5 q} \cdot 30 r = \frac{9 r^{3}}{q^{2}}2qr⋅5q3r⋅30r=q29r3