3a² + 4ab - 3b² + a² + b² + -4a² - 3ab + 2b²
asked by guest on Apr 13, 2025 at 5:09 pm
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MathBot Answer:
3a2+4ab−3b2+a2+b2+−(4a2)−3ab+2b2=ab3 {a}^{2} + 4 a b - 3 {b}^{2} + {a}^{2} + {b}^{2} + -\left( 4 {a}^{2} \right) - 3 a b + 2 {b}^{2} = a b3a2+4ab−3b2+a2+b2+−(4a2)−3ab+2b2=ab