(x ^ { 3 } -2x ^ { 2 } -mx+1) \div x+1

asked by guest
on Mar 26, 2025 at 8:53 pm



You asked:

Evaluate the expression: x3−2x2−mx+1x+1\frac{{x}^{3} - 2 {x}^{2} - m x + 1}{x} + 1

MathBot Answer:

Evaluated



x3−2x2−mx+1x+1=1+−mx+x3−2x2+1x\displaystyle \frac{{x}^{3} - 2 {x}^{2} - m x + 1}{x} + 1 = 1 + \frac{- m x + x^{3} - 2 x^{2} + 1}{x}

Expanded

x3−2x2−mx+1x+1=−m+x2−2x+1+1x\frac{{x}^{3} - 2 {x}^{2} - m x + 1}{x} + 1 = - m + x^{2} - 2 x + 1 + \frac{1}{x}

Factored

x3−2x2−mx+1x+1=−mx−x3+2x2−x−1x\frac{{x}^{3} - 2 {x}^{2} - m x + 1}{x} + 1 = - \frac{m x - x^{3} + 2 x^{2} - x - 1}{x}

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