Math Problem Solver

\[ \frac{1}{4} + \frac{1}{8} + \frac{1}{6} = \frac{13}{24} = 0.541\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{4}\), \(\frac{1}{8}\), and \(\frac{1}{6}\) is \(24\). \[ \begin{aligned} \frac{1}{4} + \frac{1}{8} + \frac{1}{6} &= \frac{1 \cdot 6}{4 \cdot 6} + \frac{1 \cdot 3}{8 \cdot 3} + \frac{1 \cdot 4}{6 \cdot 4} \\ &= \frac{6 + 3 + 4}{24} \\ &= \frac{13}{24} \end{aligned} \]