\[\int \frac{x + 1}{(x - 1)^2 (x + 1)} \, dx\]
You asked:
Evaluate the integral: \(\int{\frac{x + 1}{{\left( x - 1 \right)}^{2} \cdot \left(x + 1\right)}}dx\)
MathBot Answer:
Antiderivative
\[\int{\frac{x + 1}{{\left( x - 1 \right)}^{2} \cdot \left(x + 1\right)}}dx = - \frac{1}{-1 + x} + C\]