3x−4x−4\frac{3x-4}{x-4}x−43x−4
asked by guest on Mar 19, 2025 at 6:09 pm
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MathBot Answer:
3x−4x−4=3x−4x−4\displaystyle \frac{3 x - 4}{x - 4} = \frac{3 x - 4}{x - 4} x−43x−4=x−43x−4
3x−4x−4=3xx−4−4x−4\frac{3 x - 4}{x - 4} = \frac{3 x}{x - 4} - \frac{4}{x - 4}x−43x−4=x−43x−x−44