what are the zeros of f(x)=(x-3)(x^3-1)?

asked by guest
on Nov 16, 2024 at 7:11 pm



You asked:

Find the zeros of f(x)=(x−3)(x3−1)f\left( x \right) = \left(x - 3\right) \left({x}^{3} - 1\right).

MathBot Answer:

The real zeros of f(x)=(x3−1)(x−3)f(x)=\left(x^{3} - 1\right) \left(x - 3\right) are: x=1x=3\begin{align*}x &= 1\\x &= 3\end{align*}

The complex zeros of f(x)=(x3−1)(x−3)f(x)=\left(x^{3} - 1\right) \left(x - 3\right) are: x=−12−3i2≈−0.5−0.866025403784439ix=−12+3i2≈−0.5+0.866025403784439i\begin{align*}x &= - \frac{1}{2} - \frac{\sqrt{3} i}{2} \approx -0.5 - 0.866025403784439 i\\x &= - \frac{1}{2} + \frac{\sqrt{3} i}{2} \approx -0.5 + 0.866025403784439 i\end{align*}
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